Thursday, October 28, 2010

How much time will pass before the block falls off the table from when the other block is released?

A 12 kg block on a table is connected by a string to a 26 kg mass, which is hanging over the edge of the table. If the 12 kg block is 1.5 m from the edge of the table, how much time will pass before the block falls off the table from when the other block is released? Assume that frictional forces may be neglected.How much time will pass before the block falls off the table from when the other block is released?
Let:

m1 be the mass on the table,

m2 be the suspended mass,

g be the acceleration due to gravity,

a be the acceleration of the system,

T be the tension in the string,

x be the distance of m1 from the edge of the table,

t be the time before it falls.



For the block on the table:

T = m1 a



For the suspended block:

m2 g - T = m2 a



Adding these equations:

m2 g = (m1 + m2)a



a = m2 g / (m1 + m2)



The acceleration satisfies:

x = at^2 / 2



t^2 = 2x / a



t = sqrt[ 2x(m1 + m2) / (m2 g) ]

= sqrt[ 2 * 1.5(12 + 26) / (26 * 9.81) ]

= 0.669 sec.

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